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int(cotxtanx)/(sec^(2)x-1)dx=...

`int(cotxtanx)/(sec^(2)x-1)dx=`

A

`cotx-x+c`

B

`-cotx+x+c`

C

`cotx+x+c`

D

`-cotx-x+c`

Text Solution

Verified by Experts

The correct Answer is:
D
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