intdx/(1+e^x)...

`intdx/(1+e^x)`

A

`logabs(1+e^(x))+c`

B

`-logabs(1+e^(-x))+c`

C

`-logabs(1-e^(-x))+c`

D

`logabs(e^(-x)+e^(-2x))+c`

Text Solution

Verified by Experts

The correct Answer is:

B

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