int1/(1+cos^(2)x)dx=...

`int1/(1+cos^(2)x)dx=`

A

`1/sqrt(2)tan^(-1)(tanx)+c`

B

`1/sqrt(2)tan^(-1)(1/2tanx)+c`

C

`1/sqrt(2)tan^(-1)(1/sqrt(2)tanx)+c`

D

`sqrt(2)tan^(-1)(1/sqrt(2)tanx)+c`

Text Solution

Verified by Experts

The correct Answer is:

C

Doubtnut Promotions Banner Desktop Dark

Doubtnut Promotions Banner Mobile Dark

|

Topper's Solved these Questions

INTEGRATION
TARGET PUBLICATION|Exercise COMPETITIVE THINKING|165 Videos
INTEGRATION
TARGET PUBLICATION|Exercise EVALUATION TEST|29 Videos
INTEGRATION
TARGET PUBLICATION|Exercise EVALUATION TEST|29 Videos
DIFFERENTIATION
TARGET PUBLICATION|Exercise EVALUATION TEST|30 Videos
LINE
TARGET PUBLICATION|Exercise Evaluation Test|1 Videos

Similar Questions

Explore conceptually related problems

int(1)/(1+cos^(2)x)dx

int(1)/(1-cos^(2)x)dx=

int(1)/(1+cos^(2)x)dx=(1)/(sqrt(2))tan^(-1)((tan x)/(sqrt(2)))+c

int(1)/(1-cos^(2)x)*dx=

int(1)/(1+4cos^(2)x)dx

int(1)/(1+3cos^(2)x)dx=(1)/(2)tan^(-1)((tan x)/(2))+c

int(1)/(1+3 cos^(2) x)dx

" "int(1)/(a+b cos^(2)x)dx

int(1)/(1-cos 2x) dx

Evaluate the following integrals : int(1)/(1+cos2x)dx

TARGET PUBLICATION-INTEGRATION-CRITICAL THINKING

int(x dx)/(x^4+x^2+1)
01:42
|
int1/(1+sin^(2)x)dx=
04:01
|
int1/(1+cos^(2)x)dx=
03:26
|
int(sinx)/(3+4cos^(2)x)dx = "……."
01:13
|
int \ dx/(a^2 sin^2x + b^2 cos^2x)
01:44
|
int (dx)/((4sin^(2)x+5cos^(2)x))=?
04:45
|
int(dx)/(2sin^(2)x-3cos^(2)x+7)=
04:48
|
Evaluate int(dx)/((2+cosx)).
02:49
|
Evaluate the following integrals: int(dx)/((2sinx+cosx+3))
06:22
|
The value of int(dx)/(xsqrt(x^(4)-1)) is
02:09
|
int (x^2-1)/((x^2+1) sqrt(x^4+1)) \ dx
03:52
|
Evaluate: int(sec^2x)/(sqrt(tan^2x+4))dx
01:06
|
intsqrt(x^(2)-8x+7)dx=
03:52
|
intx/sqrt(x^(4)-4)dx=
01:43
|
inte^(x)/sqrt(e^(2x)+4e^(x)+13)dx=
03:35
|
int(1)/(sqrt(cos^(2)+cot^(2)x))dx=
03:06
|
int(dx)/(2x^(2)+x-1) is equal to
03:55
|
int(dx)/(x[(logx)^(2)+4logx-1])=
02:56
|
Evaluate: int1/((x^2-1)sqrt(x^2+1))\ dx
05:49
|
If int((2x+1))/(x^(4)+2x^(3)+x^(2)-1)dx=Alogabs((x^(2)+x+1)/(x^(2)+x-1...
04:13
|