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TARGET PUBLICATION-INTEGRATION-CRITICAL THINKING
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- int x^3tan^(-1)x dx
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- Ifintxlog(1+1/x)dx=f(x)log(x+1)+g(x)x^2+A x+C , then f(x)=1/2x^2 (b) ...
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- intsin^(-1)xdx
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- intsinsqrt(x)dx=?
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- intsqrt(x)e^(sqrt(x))dx=
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- intx^(5).e^(x^(2))dx=
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- intsin(logx)dx=
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- intsinxlog(secx+tanx)dx=
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- Evaluate: intsin^(-1)(3x-4\ x^3)\ dx
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- Evaluate: int(sin^(-1)x)/((1-x^2)^(3setminus2))\ dx
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- int(xtan^-1x)/(1+x^2)^(3/2)dx
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- intsec^(3)theta"d"theta=
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- int e^(x)""((x-1)/(x^(2)))dx is equal to
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- The value of inte^(x)(x^(5)+5x^(4)+1)dx is
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- inte^(x)[tanx-log(cosx)]dx=
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- inte^(x)(1+tanx+tan^(2)x)dx=
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- inte^(x)(1-cotx+cot^(2)x)dx=
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- int(xe^(x))/((x+1)^(2))dx=
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