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If A=[{:(a,0,0),(0,b,0),(0,0,c):}], a=7^...

If `A=[{:(a,0,0),(0,b,0),(0,0,c):}], a=7^(x), b=7^(7^(x)), c=7^(7^(7^(x))), " then " intabs(A)dx, " where " abs(A)` is the determinant of the matrix A, equals

A

`7^(7^(x))/(log7)^(3)+c`

B

`7^(7^(7^(x)))/(log7)+c`

C

`7^(7^(7^(x))).(log7)^(3)+c`

D

`(7^(7^(7^(x))))/(log7)^(3)+c`

Text Solution

Verified by Experts

The correct Answer is:
D
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