intx.sinx.sec^(3)xdx=...

`intx.sinx.sec^(3)xdx=`

A

`1/2(sec^(2)x-tanx)+c`

B

`1/2(xsec^(2)x-tanx)+c`

C

`1/2(xsec^(2)x+tanx)+c`

D

`1/2(sec^(2)x+tanx)+c`

Text Solution

Verified by Experts

The correct Answer is:

B

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