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intcosalpha/(sinxcos(x-alpha))dx=""+c, "...

`intcosalpha/(sinxcos(x-alpha))dx="_________"+c, " where " 0 le x le alpha le pi/2 " and " alpha` is constant.

A

`-logabs(cotx+tanalpha)`

B

`logabs(cotx+tanalpha)`

C

`-logabs(tanx+cotalpha)`

D

`logabs(tanx+cotalpha)`

Text Solution

Verified by Experts

The correct Answer is:
A
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