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int(1)/(16x^(2)+9)dx is equal to...

`int(1)/(16x^(2)+9)dx` is equal to

A

`1/4tan^(-1)((4x)/3)+c`

B

`1/12tan^(-1)((4x)/3)+c`

C

`1/3tan^(-1)((4x)/3)+c`

D

`1/6tan^(-1)((4x)/3)+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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