`(NH_(4))_(2)Cr_(2)O_(7)` on heating gives

Options

A. `Cr_(2)O_(3)`
B. `N_(2)`
C. `H_(2)CrO_(4)`
D. `NH_(3)`

Explanation

To solve the problem of what `(NH₄)₂Cr₂O₇` gives upon heating, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**: The compound given is ammonium dichromate, `(NH₄)₂Cr₂O₇`.

2. **Understand the Reaction**: When ammonium dichromate is heated, it undergoes a decomposition reaction.

3. **Write the Decomposition Reaction**:
The decomposition of ammonium dichromate can be represented as:
\[ (NH₄)₂Cr₂O₇ \xrightarrow{\text{heat}} Cr₂O₃ + N₂ + 4H₂O \]

4. **Identify the Products**:
- **Chromium(III) oxide**: \( Cr₂O₃ \)
- **Nitrogen gas**: \( N₂ \)
- **Water**: \( H₂O \)

5. **Count the Molecules**: From the balanced equation, we can see that for every mole of ammonium dichromate, we produce:
- 1 mole of \( Cr₂O₃ \)
- 1 mole of \( N₂ \)
- 4 moles of \( H₂O \)

6. **Conclusion**: Therefore, upon heating `(NH₄)₂Cr₂O₇`, the products formed are \( Cr₂O₃ \), \( N₂ \), and \( H₂O \).

### Final Answer:
Upon heating, `(NH₄)₂Cr₂O₇` gives:
- \( Cr₂O₃ \)
- \( N₂ \)
- \( H₂O \)