AgBr used in photography, is removed with the help of ……… called ………. And forms ………..

Options

A. `Na_(2)S_(2)O_(3)," hypo "Na_(3)[Ag(S_(2)O_(3))_(2)]`
B. Hydroquinone, `Ag, AgNO_(3)`
C. `Na_(2),SO_(4)," hypo "Na_(3)[Ag(S_(2)O_(3))_(2)]`
D. `Na_(2)S_(2)O_(3)," sodium thiosulphate, "Na_(3)[Ag(S_(2)O_(3))_(2)]`

Explanation

To answer the question about how AgBr, used in photography, is removed, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**: AgBr (Silver Bromide) is a compound used in photographic films. It is sensitive to light and forms a latent image when exposed.

2. **Determine the Chemical Agent**: The compound used to remove AgBr in photographic development is Sodium Thiosulphate.

3. **Chemical Formula**: Sodium Thiosulphate is represented by the chemical formula Na2S2O3. It is often referred to as "Hypo" in photographic processing.

4. **Reaction with AgBr**: When Sodium Thiosulphate reacts with Silver Bromide, it forms a complex compound and releases bromide ions.

5. **Products of the Reaction**: The reaction can be summarized as:
\[ 2AgBr + Na2S2O3 \rightarrow 2Ag + NaBr + Na2S4O6 \]
Here, the products include Silver (Ag), Sodium Bromide (NaBr), and a thiosulphate complex (Na2S4O6).

### Final Answer:
AgBr used in photography is removed with the help of Sodium Thiosulphate, called Hypo, and forms Silver (Ag) and Sodium Bromide (NaBr).

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