Which of the following statement(s) is/are correct with reference to `Fe^(2+) and Cu^(2+)`

Options

A. Both react with NaOH
B. `Cu^(2+)` gives blue ppt of `Cu(OH)_(2)` where as `Fe^(2+)` gives `Fe(OH)_(2)` [green ppt]
C. `Cu^(2+)` gives chocolate brown ppt whereas `Fe^(2+)` gives sky blue ppt with `K_(4)[Fe(CN)_(6)]`
D. Both have four unpaired electrons

Explanation

To determine which statements are correct regarding \( \text{Fe}^{2+} \) and \( \text{Cu}^{2+} \), we will analyze their reactions with sodium hydroxide (NaOH) and other relevant properties.

### Step 1: Analyze the reactions with NaOH

1. **Reaction of \( \text{Fe}^{2+} \) with NaOH**:
- When \( \text{Fe}^{2+} \) ions react with NaOH, they form a precipitate of iron(II) hydroxide, \( \text{Fe(OH)}_2 \).
- The reaction can be represented as:
\[ \text{Fe}^{2+} + 2 \text{NaOH} \rightarrow \text{Fe(OH)}_2 \downarrow + 2 \text{Na}^+ \]

2. **Reaction of \( \text{Cu}^{2+} \) with NaOH**:
- When \( \text{Cu}^{2+} \) ions react with NaOH, they form a precipitate of copper(II) hydroxide, \( \text{Cu(OH)}_2 \).
- The reaction can be represented as:
\[ \text{Cu}^{2+} + 2 \text{NaOH} \rightarrow \text{Cu(OH)}_2 \downarrow + 2 \text{Na}^+ \]

### Step 2: Conclusion on the statements

- Since both \( \text{Fe}^{2+} \) and \( \text{Cu}^{2+} \) react with NaOH to form precipitates, the statement regarding their reaction with NaOH is correct.

### Step 3: Additional properties

- **Solubility in water**:
- \( \text{Fe(OH)}_2 \) is slightly soluble in water, while \( \text{Cu(OH)}_2 \) is insoluble.

- **Oxidation states**:
- \( \text{Fe}^{2+} \) is in the +2 oxidation state, while \( \text{Cu}^{2+} \) is in the +2 oxidation state as well.

### Final Answer

Both \( \text{Fe}^{2+} \) and \( \text{Cu}^{2+} \) react with NaOH, making the statement regarding their reactivity with NaOH correct.

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