One of the product of the following reaction is
`KCNO+(NH_(4))_(2)SO_(4)overset(Delta)rarr`

Options

A. `NH_(4)NO_(3)`
B. `NH_(2)CONH_(2)`
C. `N_(2)`
D. `NO_(2)`

Explanation

To solve the problem of determining one of the products of the reaction between potassium cyanate (KCNO) and ammonium sulfate ((NH₄)₂SO₄) upon heating, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are potassium cyanate (KCNO) and ammonium sulfate ((NH₄)₂SO₄).

### Step 2: Understand the Reaction Type
This reaction involves an ion exchange, where the ammonium ion (NH₄⁺) from ammonium sulfate interacts with the cyanate ion (CNO⁻) from potassium cyanate.

### Step 3: Write the Ion Exchange Reaction
When KCNO and (NH₄)₂SO₄ react, the ammonium ion (NH₄⁺) will pair with the cyanate ion (CNO⁻) to form ammonium cyanate (NH₄CNO). The potassium ion (K⁺) will pair with the sulfate ion (SO₄²⁻).

### Step 4: Heating the Product
Upon heating, ammonium cyanate (NH₄CNO) undergoes a transformation. It decomposes to form urea (NH₂CONH₂) and releases ammonia (NH₃) and carbon dioxide (CO₂) as byproducts.

### Step 5: Final Product
The main product of the reaction upon heating is urea (NH₂CONH₂).

### Summary of the Reaction
The overall reaction can be summarized as follows:
1. Initial reaction:
\[ KCNO + (NH₄)₂SO₄ \rightarrow NH₄CNO + K₂SO₄ \]
2. Upon heating:
\[ NH₄CNO \xrightarrow{\Delta} NH₂CONH₂ + NH₃ + CO₂ \]

### Final Answer
One of the products of the reaction is **urea (NH₂CONH₂)**.

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