The product formed in the reaction of glycine with benzoyl chloride `+aq. NaOH` is

Options

A. `PhCOCH_(2)NH_(2)`
B. `PhCH_(2)NH_(2)`
C. `PhCONHCH_(3)`
D. `PhCONHCH_(2)CO_(2)H`

Explanation

To determine the product formed in the reaction of glycine with benzoyl chloride in the presence of aqueous NaOH, we can follow these steps:

### Step 1: Identify the Reactants
- Glycine (NH2CH2COOH) is an amino acid with an amino group (-NH2) and a carboxylic acid group (-COOH).
- Benzoyl chloride (C6H5COCl) is an acyl chloride, which can react with nucleophiles.

### Step 2: Understand the Reaction Mechanism
- The amino group (-NH2) of glycine acts as a nucleophile and attacks the carbonyl carbon of benzoyl chloride.
- This is a nucleophilic acyl substitution reaction, which can be classified as an SN2 mechanism due to the nature of the reactants.

### Step 3: Reaction Process
1. The nitrogen atom in the amino group of glycine attacks the carbonyl carbon of benzoyl chloride.
2. This leads to the formation of a tetrahedral intermediate, where the chlorine atom (Cl) is displaced as a leaving group.
3. The tetrahedral intermediate collapses, resulting in the formation of an amide bond.

### Step 4: Write the Product
- The product formed from this reaction is an amide. The structure can be represented as:
- The carbonyl group from benzoyl chloride remains, and the nitrogen from glycine is now bonded to the carbonyl carbon.
- The final product is benzamide with a glycine side chain, which can be written as:
- C6H5CONHCH2COOH (benzyloxyacetic acid).

### Final Product
- The product formed is **benzoylglycine**, which can also be represented as **C6H5CONHCH2COOH**.