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According to Arrhenius equation rate co...

According to Arrhenius equation rate constant K is equal to A `e.^(-E_(a)//RT)` . Which of the following options represents the graph of ln K vs `(1)/(T)`?

A

B

C

D

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The correct Answer is:
A
`k="A e"^(-E_(a)//"RT"):.lnk=lnA-(E_(a))/(RT)`. Hence, graph of ln k vs `(1)/(T)` will be linear with negative slope and intercept = ln A, i.e., (a).
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