`3g` of actived chacoal was added to 50mL of acetic acid solution `(0.06N)` in a flask. After an hour it was filterred and the strength of the filtrate was found to be `0.042N` . The amount of acetic adsorbed (per gram of charcoal) is:

Options

A. 42 mg
B. 54 mg
C. 18 mg
D. 36 mg

Answer

C

Explanation

Milleq of acetic acid present initially `=0.06xx60=3`
millieq of acetic acid left after adsorption
`=0.042xx50=2.1`
`therefore` millieq of acetic acid adsorbed by 3 g of charcoal
`=3-2.1=0.9meq=0.9xx60 mg=54mg`
`therefore` Amount of acetic acid adsorbed per gram of charcoal `=54/3=18` mg