Find the no. of mole of phosphorus in `92.9 g` of phosphorus assuming that molecular formula of phosphorus in `P_(4^(.)`. Also determine the no. of atoms and molecules of phosphorus in the sample.

Answer

`0.75"mol",4.52 xx 10^(23)"molecules" P_(4), 18.04 xx 10^(23)"atom"P`

Explanation

`n_(P_(4))=(92.9)/(4xx31)=0.75` mole
`N_(P_(4))=0.75xxN_(A)=4.52xx10^(23)` molecules
`N_(P)=18.04xx10^(23)` molecules