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A gaseous alkane was exploded with oxyge...

A gaseous alkane was exploded with oxygen. The volume of `O_(2)` for complete combustion to `CO_(2)` formed was in the ratio of `7:4`. The molecular formula of alkane is:

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The correct Answer is:
`C_(2)H_(6)`
`C_(n)H_(2n+2)+((3n+1))/(2)O_(2)rarr nCO_(2)+(n+1)H_(2)O`
`((3n+1)//2)/(n)=(7)/(4)implies 6n+2=7n" "impliesn=2" "C_(2)H_(6)`
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