When `2.86 g` of a mixture of `1-`butene, `C_(4)H_(8)` and butane `C_(4)H_(10)` was burned in excess of oxygen `8.80 g` of `CO_(2)` and `4:14 g` of `H_(2)O` were obtained. What is percentage by mass of butane in the mixture

Answer

`60.8%`

Explanation

`{:(C_(4)H_(8)+6O_(2)rarr4CO_(2)+4H_(2)O),(x" "4x" "5x),(C_(4)H_(10)+(13)/(2)O_(2)rarr4CO_(2)+5H_(2)O),(y" "4y" "5y),((4x+5y)xx44=8.8),(x+y=0.05" "....(I)),((4x+5y)xx18=4.14),(4x+5y=0.23" "....(II)),(y=0.03):}`
`%` by mass of `C_(6)H_(10)`
`=(0.03xx58)/(2.86)xx100=60.8%`