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A 10.0 g sample of a mixture of CaCl2 an...

A 10.0 g sample of a mixture of `CaCl_2` and `NaCl` is treated to precipitate all the calcium as calcium carbonate. Thus `CaCO_3` is heated to convert all the Ca to CaO and the final mass of CaO is 1.62 g. What is the percentage by mass of `CaCl_2` in the original mixture?

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The correct Answer is:
`67.9%`


`n_(CaCl_(2))=n_(caO)=(1.62)/(56)=0.02892`
`m_(CaCl_(2))=0.02892xx111=3.211g`
`m_(NaCl)=6.7889gm`
`%NaCl=67.9%`
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