Cadverine molecule has `58.77% C, 13.81% H` and `27% N` by mass Find Empirical formula of cadverine .

Answer

`C_(5)H_(14)N_(2)`

Explanation

`|{:("element","massper100gm","mole","simplest ratio",),(C,58.77,58.77//12,5,),(H,13.81,13.81//1,14,),(N,27.42,27.14//2,2,):}|`
`E.F = C_(5)H_(14)N_(2)=102=M.E`