Ten millilitre of a mixture of `CO,CH_4`, and `N_2` exploded with an excess of `O_2` and gave a contaction of `6.5ml`. When the residual gas was treated with `NaOH`, there was further contraction of 7 ml. What is the composition of the original mixture?

Answer

`CO=5mL,CH_(4)=2mL,N_(2)=3mL`

Explanation

`CO+(1)/(2)O_(2)rarrCO_(2)`
`x" "-x//2" "x`
`Cl_(+4)+2O_(2)rarrCO_(2)+2H_(2)O(l)`
`y" "-2y" "y`
`{:((x)/(2)+2y=6.5," "....(I)),(x+y=7," "....(II)),(x+y+z=10," "....(III)):}`
`x=5ml" "y=2ml" "z=3ml`