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When 100 ml of O2-O3 mixture was passed ...

When 100 ml of `O_2-O_3` mixture was passed through turpentine oil, there was reduction of volume by 20 ml. If 100 ml of such a mixture is heated, what will be the increase in the volume?

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The correct Answer is:
`10mL`
`O_(3)rarr(3)/(2)O_(2)`
`20" "(80)`
`(3)/(2)xx20+80=110`
Increase in volume = 110-100=10ml`
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