`1.0g` of `a` sample containing `NaCl, KCl` and some inert impurity is dissolved in excess of water and treated with excess of `AgNO_(3)` solution. `A 2.0 g` precipitate to `AgCl` separate out. Also sample is `23%` by mass in sodium. Determine mass percentage of `KCl` in the sample :

Answer

`29.28`

Explanation

Moles of `NaCl` in sample `=0.01` = moles of `AgCl` from `NaCl` in precipitate `=0.01`
Total moles of `AgCl` precipitate `=(2)/(143.5)=0.01393`
implies Moles of `AgCl` from `KCl = 0.00393` = moles of `KCl`
implies Mass of `KCl` in sample `=0.00393xx74.5=0.2928g`
Mass `%` of `KCl` in the sample `=29.28`