`Pb(NO_(3))_(2)` and `KI` reacts in aqueous solution to form an yellow precipitate of `PbI_(2)`. In one series of experiments, the masses of two reactants varied, but the total mass of the two was held constant at `5.0g`. What maximum mass of `PbI_(2)` can be produced in the above experiment :

Answer

`3.464g`

Explanation

In order to obtain maximum yield from a reaction, the reactants must be supplied in stoichiometric amount so that no reactant should be left unreacted.
The balanced chemical reaction is,
`Pb(NO_(3))_(2)+2KIrarrPbI_(2)+2KNO_(3)`
Let `x g` of `KI` is taken
implies moles of `KI=(x)/(166) `impliesmoles of `Pb(NO_(3))_(2)` present `=(x)/(2xx166)`
`implies (x)/(2xx166)=(5-x)/(330)implies x=2.5 g` implies mass of `PbI_(2)`
`=(x)/(332)xx460=3.464 g`