Fluoro carbon polymers can be made by fluorinationg polythene.
(i) `(CH_(2))_(n) + 4n Co F_(3) rarr (CF_(2))_(n) + 2 nHF + 4 nCoF_(2)`
Where `n` is large integer. The `CoF_(3)` can be regenarted by the above reaction.
(ii) `2CoF_(2) + F_(2) rarr 2CoF_(3)`
If the `HF` formed in reactionn (i) cannot be reused, calculate the weight of `F_(2)` consumed by `1.0 g` of `(CF_(2))_(n)` produced.

Answer

`1.52kg,0.76kg`

Explanation

`(CH_(2))_(n)+4nCoF_(3)rarr(CF_(2))_(n) + 2nHF+4nC0F_(2)…(1)`
`2CoF_(2)+F_(2)" "rarr2CoF_(3)`
`wt. implies F=19,C=12, Co-59,M_(wt)(CF_(2))_(n)=50n`
`{:(,"from" eq. (1),(CF_(2))_(n),=,4nCoF_(2)),(,,(w)/(E),,(w)/(E)),(,,(1000)/(50n),=,(w)/(4nxx97)):}`
`w=(1000)/(50n)xx4nxx97`
`w=80xx97g(CoF_(2))`
`because 2CoF_(2)+F_(2)rarr2CoF_(3)`
`2xx97 rarr 1xx38`
`=80xx97rarr(1xx38)/(2xx97)xx80xx97=1520g=1.52kg`.
`{:(2HFrarrH_(2)+F_(2)),(40" "20):}{{:(because(CF_(2))_(n)"moles"=(1000)/(50n)=(20)/(n)"moles of"(CF_(2))_(n) ),(" "2nHFxx(20)/(n)=40"mol"):}`
`1rarr(20)/(40)xx1.52`
`1.52=0.76 kg`