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A sample of oleum is such that ratio of ...

A sample of oleum is such that ratio of free `SO_(3)` by combined `SO_(3)` is equal to unity. Calculate its labelling in terms of percentage oleum.

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The correct Answer is:
`110.11%`
Let free `SO_(3)rarr xg`
`SO_(3)` in form of `H_(2)SO_(4)`
`rarr(x)/(80)xx98=1.225x`
so total
`x+1.225x=100`
`x=449.49`
water required `=(44.94)/(80) xx18 = 10..11 g%` oleum `=100+10.11=110.11%`
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