The ratio of number of oxygen atoms `(O)` in `16.0g` ozone `(O_(3)) . 28.0g` carbon monoxide `(CO)` and `16.0g` oxygen `(O_(2))` is :-
`("Atomic mass" : C=12,O=16 "and Avogadro's constant" N_(A) =6.0xx10^(23) "mol"^(-1))`

Options

A. `3:1:1`
B. `1:1:2`
C. `3:1:2`
D. `1:1:1`

Answer

To solve the problem, we need to find the number of oxygen atoms in 16.0 g of ozone (O₃), 28.0 g of carbon monoxide (CO), and 16.0 g of oxygen (O₂). We will then calculate the ratio of these quantities.

### Step 1: Calculate the number of moles of Ozone (O₃)

The molar mass of ozone (O₃) can be calculated as follows:
- Molar mass of O = 16 g/mol
- Molar mass of O₃ = 3 × 16 g/mol = 48 g/mol

Now, we can find the number of moles of ozone in 16.0 g:
\[ \text{Moles of O₃} = \frac{\text{mass}}{\text{molar mass}} = \frac{16.0 \text{ g}}{48 \text{ g/mol}} = \frac{1}{3} \text{ mol} \]

### Step 2: Calculate the number of oxygen atoms in Ozone (O₃)

Since each molecule of ozone contains 3 oxygen atoms, the number of oxygen atoms in 16.0 g of O₃ is:
\[ \text{Number of O atoms in O₃} = \text{Moles of O₃} \times 3 \times N_A = \frac{1}{3} \text{ mol} \times 3 \times 6.022 \times 10^{23} \text{ atoms/mol} = 6.022 \times 10^{23} \text{ atoms} \]

### Step 3: Calculate the number of moles of Carbon Monoxide (CO)

The molar mass of carbon monoxide (CO) is:
- Molar mass of C = 12 g/mol
- Molar mass of O = 16 g/mol
- Molar mass of CO = 12 g/mol + 16 g/mol = 28 g/mol

Now, we can find the number of moles of CO in 28.0 g:
\[ \text{Moles of CO} = \frac{28.0 \text{ g}}{28 \text{ g/mol}} = 1 \text{ mol} \]

### Step 4: Calculate the number of oxygen atoms in Carbon Monoxide (CO)

Since each molecule of CO contains 1 oxygen atom, the number of oxygen atoms in 28.0 g of CO is:
\[ \text{Number of O atoms in CO} = \text{Moles of CO} \times 1 \times N_A = 1 \text{ mol} \times 1 \times 6.022 \times 10^{23} \text{ atoms/mol} = 6.022 \times 10^{23} \text{ atoms} \]

### Step 5: Calculate the number of moles of Oxygen (O₂)

The molar mass of oxygen (O₂) is:
- Molar mass of O₂ = 2 × 16 g/mol = 32 g/mol

Now, we can find the number of moles of O₂ in 16.0 g:
\[ \text{Moles of O₂} = \frac{16.0 \text{ g}}{32 \text{ g/mol}} = 0.5 \text{ mol} \]

### Step 6: Calculate the number of oxygen atoms in Oxygen (O₂)

Since each molecule of O₂ contains 2 oxygen atoms, the number of oxygen atoms in 16.0 g of O₂ is:
\[ \text{Number of O atoms in O₂} = \text{Moles of O₂} \times 2 \times N_A = 0.5 \text{ mol} \times 2 \times 6.022 \times 10^{23} \text{ atoms/mol} = 6.022 \times 10^{23} \text{ atoms} \]

### Step 7: Calculate the ratio of oxygen atoms

Now we can sum up the number of oxygen atoms from each source:
- Ozone (O₃): \(6.022 \times 10^{23}\) atoms
- Carbon Monoxide (CO): \(6.022 \times 10^{23}\) atoms
- Oxygen (O₂): \(6.022 \times 10^{23}\) atoms

Total oxygen atoms:
\[ \text{Total O atoms} = 6.022 \times 10^{23} + 6.022 \times 10^{23} + 6.022 \times 10^{23} = 18.066 \times 10^{23} \text{ atoms} \]

Now, we can express the ratio of the number of oxygen atoms:
\[ \text{Ratio} = \text{O atoms in O₃} : \text{O atoms in CO} : \text{O atoms in O₂} = 6.022 : 6.022 : 6.022 = 1 : 1 : 1 \]

### Final Answer:
The ratio of the number of oxygen atoms in 16.0 g of ozone, 28.0 g of carbon monoxide, and 16.0 g of oxygen is **1 : 1 : 1**.