Calculate molar conductance for `NH_(4)OH`, given that molar conductance for `Ba(OH)_(2), BaCI_(2)` and `NH_(4)CI` are `523.28, 280.0` and `129.8 ohm^(-1) cm^(2) mol^(-1)` respectively.

Explanation

To calculate the molar conductance of \( NH_4OH \), we can use the molar conductance values of the compounds provided: \( Ba(OH)_2 \), \( BaCl_2 \), and \( NH_4Cl \). Here's a step-by-step breakdown of the solution:

### Step 1: Write the Molar Conductance Equations
1. **For \( Ba(OH)_2 \)**:
\[ \Lambda_{m}(Ba(OH)_2) = \Lambda_{m}(Ba^{2+}) + 2 \Lambda_{m}(OH^{-}) \]
Given: \( \Lambda_{m}(Ba(OH)_2) = 523.28 \, \Omega^{-1} cm^2 mol^{-1} \)
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