The weight of solute present in 200mL of...

The weight of solute present in 200mL of `0.1M H_(2)SO_(4)`:

`2.45g`

`4.9g`

`1.96g`

`3.92g`

Text Solution

Verified by Experts

The correct Answer is:

`n =(0.1 xx 98)/(5) =1.96gm`

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