1000 gram aqueous solution of `CaCO_(3)` contains 10 gram of carbonate. Concentration of solution is:

Options

A. 10 p pm
B. 100 ppm
C. 1000 ppm
D. 10,000 ppm

Explanation

To find the concentration of the aqueous solution of \( \text{CaCO}_3 \) in parts per million (ppm), we can follow these steps:

### Step 1: Understand the definition of ppm
Parts per million (ppm) is defined as the mass of solute (in grams) per million grams of solution. The formula for calculating ppm is:
\[ \text{ppm} = \left( \frac{\text{mass of solute (g)}}{\text{mass of solution (g)}} \right) \times 10^6 \]

### Step 2: Identify the mass of solute and solution
From the problem, we know:
- Mass of solute (carbonate) = 10 grams
- Mass of solution = 1000 grams

### Step 3: Substitute the values into the ppm formula
Now, we can substitute the values into the ppm formula:
\[ \text{ppm} = \left( \frac{10 \, \text{g}}{1000 \, \text{g}} \right) \times 10^6 \]

### Step 4: Calculate the ppm
Calculating the fraction:
\[ \frac{10}{1000} = 0.01 \]
Now, multiply by \( 10^6 \):
\[ \text{ppm} = 0.01 \times 10^6 = 10,000 \]

### Step 5: Final answer
Thus, the concentration of the solution is:
\[ \text{Concentration} = 10,000 \, \text{ppm} \]