Number of tertiary bromide of formula `C_(5)H_(11)Br` are `(X)`
number of tertiary bromide of formula `C_(6)H_(13)Br` are `(Y)`
Report your answer as `X + Y`

Explanation

To solve the problem, we need to determine the number of tertiary bromides for the given formulas \( C_5H_{11}Br \) and \( C_6H_{13}Br \).

### Step-by-Step Solution:

1. **Identify Tertiary Bromides for \( C_5H_{11}Br \)**:
- A tertiary bromide has the bromine atom attached to a carbon that is bonded to three other carbon atoms.
- For \( C_5H_{11}Br \), we can draw the structure:
- The structure can be represented as:
\[ CH_3-CH_2-C(CH_3)(Br)-CH_3 \]
- Here, the central carbon is bonded to three other carbons (two methyl groups and one ethyl group), making it a tertiary carbon.
- **Count**: There is only **1** structure possible for \( C_5H_{11}Br \).

2. **Identify Tertiary Bromides for \( C_6H_{13}Br \)**:
- For \( C_6H_{13}Br \), we can have multiple structures:
- First structure:
\[ CH_3-CH_2-CH_2-C(CH_3)(Br)-CH_3 \]
- Second structure:
\[ CH_3-CH_2-C(CH_3)(CH_2Br)-CH_3 \]
- Third structure:
\[ C(CH_3)(CH_3)(CH_2Br)-CH_3 \]
- Here, we can see that there are **3** distinct structures possible for \( C_6H_{13}Br \).

3. **Calculate \( X + Y \)**:
- From the above, we have:
- \( X = 1 \) (for \( C_5H_{11}Br \))
- \( Y = 3 \) (for \( C_6H_{13}Br \))
- Therefore, \( X + Y = 1 + 3 = 4 \).

### Final Answer:
The final answer is \( 4 \).

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