Adenine is a substituted form of a heterocyclic nitrogenous base Purine. Adenine is found in both polymers `DNA` and `RNA`. Adenine is composed of the elements carbon, hydrogen and nitrogen and has molecular mass of `13.5 amu`. Upon analysis, it was found that the ratio of `%` (by `w.t.`) of carbon to that of total `%` (by `wt`) of hydrgoen and nitrogen was found to be `4:5` respectively. The ratio of number of `N` atoms to hydrogen atoms is `1 : 1`.
Now, answer the following questions:
The amount of glucose `(C_(6)H_(12)O_(6))` obtained when all the carbon in `36 mg` of adenine is converted into glucose is :

Options

A. `0.22 m` mole
B. `0.26 m` mole
C. `48 mg`
D. `40 mg`

Answer

A, D

Explanation

Adenine `rarr` Glucose
Applying `POAC` on `C`
`5 xx (36 xx 10^(-3))/(135) = 6 xx (wt)/(180) :.` weight `(C_(6)H_(12)O_(6))`
`= 40 xx 10^(-3)g = 40 mg rArr m` mole `= (40)/(180) = (2)/(9) = 0.222`