A mixture contaning `1 mol` each of `CO` and `O_(2)` is exploded to produce `CO_(2)`. Which of the following is/are correct ?

Options

A. If `%` yield of reaction is `80%`, only `0.8` mole `CO_(2)` is formed.
B. Oxygen is limiting reagent.
C. Volume of final gaseous mixture is `33.6L` at `STP`, if `%` yield is `100%`
D. `%` excess of excess reagent is `40%`, if `%` yield is `100%`

Answer

A, C

Explanation

`{:(2CO,+,O_(2)rarr,2CO_(2),),(,,CO is L.R. ,, O_(2) "is excess reagent"),(t=t,,1mol, 1mol),(t=t,o mol,1/2mol,mol("If % yield is 100%")):}`
Total gaseous moles `= 1 + (1)/(2) = 1.5 mol`
`:.` Volume of final mixture `1.5 xx 22.4 = 33.6L`
`%` excess of `O_(2) = (1//2"mol")/(1//2"mol") xx 100 = 100%`
If `%` yield `= 80`
`= ("Actual moles of" CO_(2) "formed")/("moles of" CO_(2) ("accoding to stoichiometry"))xx 100`
`80 = ("Moles of" CO_(2)"formed")/(1) xx 100`
`:.` Actual moles formed `= 0.8 mol`