T-V curve of cyclic process is shown below, number of moles of the gas are n find the total work done during the cycle.

Explanation

Since path `AB` and `CD` are isochoric therefore work done is zero during path `AB` and `CD`. Process `BC` and `DA` are isothermal, therefore
`W_(BC) = nRT_(2) In(V_(C))/(V_(B)) = 2nRT_(0) In2`
`W_(DA) = nRT_(0) In (V_(A))/(V_(D)) =- nRT In 2`
Total work done `=W_(BC) +W_(DA) = 2nRT_(0) In -nRT_(0) In2 = nRT_(0) In 2`