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The work of 142kJ is performed in order ...

The work of 142kJ is performed in order to compress one kilo mole of gas adiabatically and in this process the temperature of the gas increases by `7^@C`. The gas is `(R=8.3Jmol^-1K^-1)`

A

diatomic

B

triatomic

C

mixture of monoatomic and diatomic

D

monoatomic

Text Solution

Verified by Experts

The correct Answer is:
A
For adiabatic , `W = (P_(1)V_(1)-P_(2)V_(2))/(gamma-1) = (nR(T_(1)-T_(2)))/(gamma-1)`
Putting values, we get `gamma = 1.4`, hence diatomic.
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