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When a system is taken from state i to state f along the path iaf, it is found that `Q=50 cal and W=20 cal`. Along the path ibf `Q=36cal`. W along the path ibf is

A

`6 cal`

B

`16 cal`

C

`66cal`

D

`14cal`

Text Solution

Verified by Experts

The correct Answer is:
A
From first law of thermodynamics,
`Q = DeltaU +W`
For path iaf,
`50 = DeltaU +20`
`:. DeltaU = U_(f) - U_(i) = 30 cal`
For path ibf,
or `Q = DeltaU +W`
`W = Q - DeltaU = 36 - 30 = 6cal`.
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