Prove that `sin theta sin(60^(@)-theta) sin(60^(@)+theta)=1/4 sin3theta`.

Explanation

To prove that \( \sin \theta \sin(60^\circ - \theta) \sin(60^\circ + \theta) = \frac{1}{4} \sin 3\theta \), we will break down the left-hand side step by step.

### Step 1: Write the left-hand side
We start with the left-hand side of the equation:
\[ LHS = \sin \theta \sin(60^\circ - \theta) \sin(60^\circ + \theta) \]

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