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In triangle A B C ,tanA+tanB+tanC=6a n d...

In triangle `A B C ,tanA+tanB+tanC=6a n dtanAtanB=2,` then the values of `tanA ,tanB ,tanC` are, respectively `1,2,3` (b) `3,2//3,7//3` `4,1//2` `,3//2` (d) none of these

A

3,1,2

B

1,2,4

C

1,2,3

D

2,2,2

Text Solution

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The correct Answer is:
C
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