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If alpha+beta=pi/2a n dbeta+gamma=alpha,...

If `alpha+beta=pi/2a n dbeta+gamma=alpha,` then `tanalpha` equals `2(tanbeta+tangamma)` (b) `tanbeta+tangamma` `tanbeta+2tangamma` (d) `2tanbeta+tangamma`

A

`2(tanbeta + tangamma)`

B

`tanbeta + 2tangamma`

C

`tanbeta - tangamma`

D

`tangamma -tanbeta`

Text Solution

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The correct Answer is:
B
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