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The general solution of sin^2 theta sec ...

The general solution of `sin^2 theta sec theta +sqrt3 tan theta=0` is `(n in 1)`

A

`theta = npi+(-1)^(n+1)pi/3, theta=npi, n int I`

B

`theta = npi, n int I`

C

`theta = npi +(-1)^(n+1)pi/3, n int I`

D

`theta = (npi)/2, n int I`

Text Solution

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The correct Answer is:
B
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