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The solution of equation (sin3x)/(2cos2...

The solution of equation `(sin3x)/(2cos2x+1)=1/2` is

A

`x=3npi + pi/6`

B

`x = npi-pi/6`

C

`x = npi+(-1)^(n)pi/3`

D

`x= npi + (-1)^(n)pi/6`

Text Solution

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The correct Answer is:
D
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