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In a triangle ABC, we have acosB+bcosC...

In a triangle ABC, we have `acosB+bcosC+ccosA=(a+b+c)/2` where A, B, C are internal angles and a, b,c are length of sides opposite to them respectively.Then must be

A

The triangle is isosceles

B

The triangle is equilateral

C

The triangle is isosceles right angled

D

The triangle is right angled

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AAKASH INSTITUTE-TRIGNOMETRIC FUNCTIONS -Section-B (Objective Type Questions One option is correct)
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