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If cos2alpha=(3cos2beta-1)/(3-cos2beta)...

If `cos2alpha=(3cos2beta-1)/(3-cos2beta)`, then tan `alpha` is equal to

A

`sqrt(2)tanbeta`

B

`-sqrt(2)tanbeta`

C

`1/sqrt(2)tanbeta`

D

`-1/sqrt(2)tanbeta`

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The correct Answer is:
A, B
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