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sinalpha*sin(60-alpha)sin(60+alpha) = 1/...

`sinalpha*sin(60-alpha)sin(60+alpha) = 1/4*sin3alpha`

A

`(4pi)/3`

B

`-(5pi)/3`

C

`(2pi)/3`

D

`(5pi)/3`

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A, B, C, D
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