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A particle is projected with a speed 10s...

A particle is projected with a speed `10sqrt(2)` making an angle `45^(@)` with the horizontal . Neglect the effect of air friction. Then after 1 second of projection . Take `g=10m//s^(2)`.

A

the height of the aprticle above the point of projection is `5m`.

B

the height of the particle above the point of projection is `10m.`

C

the horizontal distance of the particle from the point of projection is `5m`.

D

the horizontal distance of the particle from the point of projection is `15m`.

Text Solution

Verified by Experts

The correct Answer is:
A
`y=u_(x)t-(1)/(2)."gt"^(2)=10xx1-5xx1^(2)=5m`
`x=u_(x)t=10xx1=10m`
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