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Block A in the figure is released from t...

Block `A` in the figure is released from the rest when the extension in the spring is `x_(0)`. The maximum downward displacement of the block will be `:`

A

`Mg//2k-x_(0)`

B

`Mg//2k+x_(0)`

C

`2Mg//k-x_(0)`

D

`2Mg//k+x_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
From work, energy theorem `:`
`W_(g)+U_(i)0U_(f)=DeltaK`
`Mgh+(1)/(2)K(x_(0)^(2)-(x_(0)+2h)^(2))=-Mgh`
`rArr (1)/(2)K(x_(0)+x_(0)+2h)(x_(0)-x_(0)-2h)=-Mgh`
`rArr (1)/(2)K2(x_(0)+h)(-2h)=-Mgh`
`h=(Mg)/(2K)-x_(0).`
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