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Mass m is connected with an ideal spring...

Mass `m` is connected with an ideal spring of natural length `l` whose other end is fixed on a smooth horizontal table. Initially spring is in its natural length `l`. Mass `m` is given a velocity `'v'` perpendicular to the spring and released . The velocity perpendicular to the spring when its length `l+x` , will be

A

`(2vl)/(l+x)`

B

`(2v^(2)+l)/(l+x)`

C

`(vl)/(l+x)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
since torque about `O` is zero.
angular momentum of mass `m` is conserved
`:. Mvl=mv_(_|_) (l+x), v_(_|_) =(vl)/(l+x)`
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