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For ground to ground projectile motion e...

For ground to ground projectile motion equation of path is `y=12x-3//4x^(2)`. Given that `g=10ms^(-2)`. What is the range of the projectile ?

A

`36 m`

B

`30.6 m`

C

`16 m`

D

`12.4m`

Text Solution

Verified by Experts

The correct Answer is:
C
`y=12 xx-((13)/(4))x^(2)=12 xx(1-(x)/(16))`
`rArr` Range `=16 m`.
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RESONANCE-DAILY PRACTICE PROBLEM-DPP No.11
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