A particle is projected from the inclined plane at angle `37^(@)` with the inclined plane in upward direction with speed `10m//s`. The angle of inclined plane with horizontal is `53^(@)`. Then the maximum height attained by the particle from the inclined plane will be-

Options

A. `3m`
B. `4m`
C. `5m`
D. zero

Answer

A

Explanation

Maximum height from inclined plane is
`H=(u_(bot)^(2))/(2a_(bot))=((10 sin 37^@)^(2))/(2g cos 53^(@))=3m`.