In the circuit in figure, the current flowing `5 Omega` resistance is :

Options

A. 0.5 A
B. 0.6 A
C. 0.9 A
D. 1.5 A

Answer

B

Explanation

`I_(2)=(R_(1))/(R_(1)+R_(2))I=(10)/(35)xx2.1 =(21)/(35)=(3)/(5)`
`I_(2) =0.6A`.